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13=5x^2-35x+73
We move all terms to the left:
13-(5x^2-35x+73)=0
We get rid of parentheses
-5x^2+35x-73+13=0
We add all the numbers together, and all the variables
-5x^2+35x-60=0
a = -5; b = 35; c = -60;
Δ = b2-4ac
Δ = 352-4·(-5)·(-60)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-5}{2*-5}=\frac{-40}{-10} =+4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+5}{2*-5}=\frac{-30}{-10} =+3 $
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